6(a+1)=4[a-(2-a)]

Solution for 6(a+1)=4[a-(2-a)] equation:

Simplifying
6(a + 1) = 4[a + -1(2 + -1a)]

Reorder the terms:
6(1 + a) = 4[a + -1(2 + -1a)]
(1 * 6 + a * 6) = 4[a + -1(2 + -1a)]
(6 + 6a) = 4[a + -1(2 + -1a)]
6 + 6a = 4[a + (2 * -1 + -1a * -1)]
6 + 6a = 4[a + (-2 + 1a)]

Reorder the terms:
6 + 6a = 4[-2 + a + 1a]

Combine like terms: a + 1a = 2a
6 + 6a = 4[-2 + 2a]
6 + 6a = [-2 * 4 + 2a * 4]
6 + 6a = [-8 + 8a]

Solving
6 + 6a = -8 + 8a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-8a' to each side of the equation.
6 + 6a + -8a = -8 + 8a + -8a

Combine like terms: 6a + -8a = -2a
6 + -2a = -8 + 8a + -8a

Combine like terms: 8a + -8a = 0
6 + -2a = -8 + 0
6 + -2a = -8

Add '-6' to each side of the equation.
6 + -6 + -2a = -8 + -6

Combine like terms: 6 + -6 = 0
0 + -2a = -8 + -6
-2a = -8 + -6

Combine like terms: -8 + -6 = -14
-2a = -14

Divide each side by '-2'.
a = 7

Simplifying
a = 7